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Is a^i^2 | i>=1 regular?

score 325 · Answer 1 · 2013-12-13 22:32:35

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Is a^i^2 | i>=1 regular?

325 views Asked by peeyush.cray At 13 December 2013 at 22:32

score 174 · Answer 2 · 2017-08-29 11:26:38

Relation of pumping lengths between related regular languages

174 views Asked by Jim Newton At 29 August 2017 at 11:26

score 267 · Answer 3 · 2011-02-06 22:19:04

Finding errors in pumping lemma conditions

267 views Asked by Mooh At 06 February 2011 at 22:19

score 18865 · Answer 4 · 2013-08-24 22:44:40

What exactly is the 'pumping length' in the Pumping lemma?

18.8k views Asked by Ivan Prodanov At 24 August 2013 at 22:44

score 798 · Answer 5 · 2013-08-25 09:02:51

Did I apply pumping lemma correctly?

798 views Asked by Ivan Prodanov At 25 August 2013 at 09:02

score 1801 · Answer 6 · 2014-01-09 02:57:55

Pumping lemma on regular languages?

1.8k views Asked by Dr. Programmer At 09 January 2014 at 02:57

score 67 · Answer 7 · 2023-10-17 00:10:55

Why pumping lemma for context free languages do not have bound on first part of string?

67 views Asked by Kapil At 17 October 2023 at 00:10

score 2219 · Answer 8 · 2011-10-18 16:42:46

Prove language irregular with pumping Lemma

2.2k views Asked by user1001606 At 18 October 2011 at 16:42

score 378 · Answer 9 · 2020-12-08 22:57:48

Discrete Logarithm in Prolog

378 views Asked by AudioBubble At 08 December 2020 at 22:57

score 1224 · Answer 10 · 2021-04-24 12:39:21

Is L = {ww^Ru | w, u ∈ {0,1}+} regular language?

1.2k views Asked by Charles Zhang At 24 April 2021 at 12:39

TechQA.

List Question

Is a^i^2 | i>=1 regular?

Relation of pumping lengths between related regular languages

Finding errors in pumping lemma conditions

What exactly is the 'pumping length' in the Pumping lemma?

Did I apply pumping lemma correctly?

Pumping lemma on regular languages?

Why pumping lemma for context free languages do not have bound on first part of string?

Prove language irregular with pumping Lemma

Discrete Logarithm in Prolog

Is L = {ww^Ru | w, u ∈ {0,1}+} regular language?

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