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PHP: How to create function which will be accessible with :: (double colon, scope resolution) in another classes

score 221 · Answer 1 · 2019-10-13T19:25:13.947000

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PHP: How to create function which will be accessible with :: (double colon, scope resolution) in another classes

221 views Asked by neologyc At 13 October 2019 at 19:25

score 141 · Answer 2 · 2019-03-04T16:17:03.763000

Scope resolution in templated inheritance (possibly what is called mixin)

141 views Asked by user647486 At 04 March 2019 at 16:17

score 2283 · Answer 3 · 2019-02-17T10:04:56.247000

Using fully qualified name for std namespace in C++

2.2k views Asked by Kam At 17 February 2019 at 10:04

score 514 · Answer 4 · 2018-08-20T15:17:38.150000

What is the purpose of "::delete" in C++?

514 views Asked by Bryan Muscedere At 20 August 2018 at 15:17

score 467 · Answer 5 · 2018-08-02T23:29:05.607000

Unable to initialize new List as value of a Map with the :: Operator?

467 views Asked by alistairv At 02 August 2018 at 23:29

score 289 · Answer 6 · 2018-07-25T09:41:30.600000

Formally correct way to explicitly call destructor of typedef'd class type

289 views Asked by Alexander Klauer At 25 July 2018 at 09:41

score 180 · Answer 7 · 2018-07-05T19:49:47.190000

Why is `::` called the 'scope resolution operator' when it doesn't act like an operator?

180 views Asked by Omnifarious At 05 July 2018 at 19:49

score 230 · Answer 8 · 2018-02-24T09:46:51.540000

How to access a header member type without scope resolution operator in C++?

230 views Asked by AudioBubble At 24 February 2018 at 09:46

score 171 · Answer 9 · 2018-02-16T07:04:18.637000

How to access function scope variables in c++?

171 views Asked by mman At 16 February 2018 at 07:04

score 12441 · Answer 10 · 2017-11-29T06:45:15.087000

What does C++ syntax “A::B:A {};” mean

12.4k views Asked by devsh At 29 November 2017 at 06:45

score 600 · Answer 11 · 2017-10-15T03:17:29.933000

Can the scope resolution operator be used in the definition of a member function when the member function is defined outside of its class definition?

score 536 · Answer 12 · 2017-05-25T11:00:29.847000

when do we use scope resolution operator before new ( ::new)?

536 views Asked by laksbv At 25 May 2017 at 11:00

score 1508 · Answer 13 · 2017-05-10T11:05:03.367000

Private Derived Destructor

1.5k views Asked by Sahib Yar At 10 May 2017 at 11:05

score 639 · Answer 14 · 2016-12-22T03:59:13.477000

C++- "using" keyword or using namespace name with scope resolution operator

639 views Asked by Prothom Ontim At 22 December 2016 at 03:59

score 1078 · Answer 15 · 2016-11-23T07:19:17.400000

Scope Resolution Operator in SQL SERVER

1k views Asked by Pரதீப் At 23 November 2016 at 07:19

score 2891 · Answer 16 · 2016-11-06T04:02:31.610000

c++ - iterating through a map of 3 elements

2.8k views Asked by RockAndaHardPlace At 06 November 2016 at 04:02

score 773 · Answer 17 · 2016-10-18T03:37:47.107000

not declare in scope when compiled g++

773 views Asked by what At 18 October 2016 at 03:37

score 105 · Answer 18 · 2016-10-13T03:25:18.910000

Applying scope resolution operator causes compiler to choke

105 views Asked by Trevor Hart At 13 October 2016 at 03:25

score 937 · Answer 19 · 2016-02-08T06:25:46.173000

Pimpl, private class forward declaration, scope resolution operator

937 views Asked by Quokka At 08 February 2016 at 06:25

score 1092 · Answer 20 · 2015-11-11T15:46:08.477000

How to call function with same name as class member

1k views Asked by Martin Heralecký At 11 November 2015 at 15:46

TechQA.

List Question

PHP: How to create function which will be accessible with :: (double colon, scope resolution) in another classes

Scope resolution in templated inheritance (possibly what is called mixin)

Using fully qualified name for std namespace in C++

What is the purpose of "::delete" in C++?

Unable to initialize new List as value of a Map with the :: Operator?

Formally correct way to explicitly call destructor of typedef'd class type

Why is `::` called the 'scope resolution operator' when it doesn't act like an operator?

How to access a header member type without scope resolution operator in C++?

How to access function scope variables in c++?

What does C++ syntax “A::B:A {};” mean

Can the scope resolution operator be used in the definition of a member function when the member function is defined outside of its class definition?

when do we use scope resolution operator before new ( ::new)?

Private Derived Destructor

C++- "using" keyword or using namespace name with scope resolution operator

Scope Resolution Operator in SQL SERVER

c++ - iterating through a map of 3 elements

not declare in scope when compiled g++

Applying scope resolution operator causes compiler to choke

Pimpl, private class forward declaration, scope resolution operator

How to call function with same name as class member

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