I would like ask for some help for advanced scala developers. My problem is that I would like to access a type alias belonging to a type parameters of a class' parent.
  case class MyModel(foo: String = "bar")
  case class MyDispatcher()
  trait Module[M, D] {
    type Dispatcher = D
    type Model = M
  }
  trait MySpecificModule[A <: Module[_, _]] {
    def dispatcher(): A#Dispatcher
  }
  class ModuleClass extends Module[MyModel, MyDispatcher] {
    //...
  }
  class MySpecificModuleClass extends MySpecificModule[ModuleClass] {
    override def dispatcher(): MyDispatcher = MyDispatcher()
  }
So basically MySpecificModule extends a generic trait, and should know the type of the dispatcher method. In this case of MySpecificModuleClass it should be MyDispatcher. But when I try to compile this code I am getting compilation error because the type of the method, is not the same as defined: A#Dispatcher, however in the reality it is.
Error:(21, 18) overriding method dispatcher in trait MySpecificModule of type ()_$2;
 method dispatcher has incompatible type
    override def dispatcher(): MyDispatcher = MyDispatcher()
             ^
I would appreciate any advice you suggest. Thanks in advance, Gabor
Resolved
case class MyModel(foo: String = "bar")
case class MyDispatcher()
trait AbstractModule {
  type Dispatcher
  type Model
}
trait Module[M, D] extends AbstractModule {
  type Dispatcher = D
  type Model = M
}
trait MySpecificModule[A <: AbstractModule] {
  def dispatcher(): A#Dispatcher
}
class ModuleClass extends Module[MyModel, MyDispatcher] {
  //...
}
class MySpecificModuleClass extends MySpecificModule[ModuleClass] {
  override def dispatcher(): MyDispatcher = MyDispatcher()
}
				
                        
I don't fully understand Scala's reasoning here, but if you get rid of type parameters, things start to work:
And if you really want to have those type params, you can introduce a helper trait: