How to make two functions with same names in Base class?

Question

This code compiled.

struct A
{
    const int *getX() const
        {
            return &x;
        }

    int *getX()
        {
            const A *thisConst = this;
            return const_cast<int *>(thisConst->getX());
        }


    void f()
        {
            int *p = getX();
        }

    int x;
};

But this code didn't.

struct I
{
    virtual const int *getX() const = 0;

    int *getX()
        {
            const I *thisConst = this;
            return const_cast<int *>(thisConst->getX());
        }
};

struct A : I
{
    virtual const int *getX() const
        {
            return &x;
        }

    void f()
        {
            int *p = getX();
        }

    int x;
};

'const_cast' : cannot convert from 'const int *' to 'int *'

I know that if I will give different names it will be compiled. But are there ways without functions renaming?

Answer 1

'const_cast' : cannot convert from 'const A *' to 'int *'

I didn't get this error while trying to compile your program, instead I got

error: invalid conversion from 'const int*' to 'int*' [-fpermissive]

To compile successfully I corrected following line

int *p = getX();

to

const  int *p = getX(); 

const int * and int* are two different types, you can't assign it directly without cast or modify the type of the variable p.