I am working on a small encryption program which takes in a message, such as "Hello there!". Whenever I run the program with a message it produces the same encrypted result "Hu8z209=yTu83tu8". If I approached breaking the encryption using differential cryptanalysis, I could learn that there is no randomization in the algorithm. But what would this actually help me to learn in order to break the encryption?
What flaws are exposed if encrypted version of plain message is always the same?
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The easiest thing is that it tells the MITM when your behavior changes.
Setup: Every day you send a report at 0800 Encrypt("No enemy sighted"). The enemy notices this.
Scenario 1: One day after they've started 'sneaking' toward you you send a different message. They know they were spotted and move into an all-out charge before your reinforcements arrive.
Scenario 2: Imagine the enemy isn't invading and your message changes. They note this. Eventually they note the message changes every 8 days. If the message changes after only 6 days it means either a) you sent a different message or b) you changed your key/schedule. They'll possibly know which tomorrow.
So both of these scenarios told "the enemy" something. They could combine both to send an all-clear on your behalf right after they invade (the day after your keys change), giving them an 7 day head start on the next outpost. If the message ALWAYS changes, because of a random nonce/IV they get no information, and if the nonces are checked for duplicates by the receiver then they also prevent replayability.
But really this question belongs on http://crypto.stackexchange.com.