I am trying to port a Qt application to C++ using STL. What is the equivalent of QVariant in C++? QVariant can store any data type - a container that holds heterogenous - different types of objects. However, I have to port this application to C++. What is the equivalent of QVariant in C++?
What is the equivalent of QVariant in C++?
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Leon Timmermans
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Starting in C++17, there is std::any (may contain a value of any copyable type) and std::variant (may contain a value of any of the given types). These will be supported out of the box in GCC 7, Clang 4.0 and Visual C++ 2017.
Neither of these is entirely equivalent (for example they don't support converting the internal value), but they will allow you to do most of what QVariant does.
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The equivalent in C++ is called
QVariant.Semi-joke aside, it is probably the closest to union, but QVariant is so much more than that; meta types, CoW, etc.
Actually, sharing implicitly is forbidden these days in STL, so that is another reason why you would not find anything like this off-hand.
I would suggest to make notes to yourself what functionality exactly you need from a QVariant and make a judgement call whether it is actually worth dropping QtCore.
This is just a friendly reminder from the documentation:
However, since C++11 types with constructors and destructors are allowed. You have another question in here to ask from yourself:
To be fair, you could also look into the following boost variants below, but then you end up using boost instead of QtCore after the porting.
This is another judgement call for yourself. They are not replacements for each other, neither technically, nor compatibility wise.
Boost in this case is a build time dependency, while QtCore is a runtime. Qt would guarantee binary (and source) compatibility during the life cycle of the same major version, while boost may not do the same for such a long period as QtCore does.
Either way, none of these options are pure
STLsolutions in the end of the day the way I think you wanted it to.Boost.Any
Boost.Variant