Git ignore how to only take the "last" file by name

Question

I have a directory in the format: ~/models/*/*, where the second * represents 220 directories named hmm0 to hmm220.

I only want to include the last directory in the commit, which I have managed to do with the .gitignore file using a sequence of ! and ignore lines (this already works):

!models/
models/*
!models/*/
models/*/*
!models/*/hmm220/

However, the issue is that the number of directories can change. For example, I may have 240 directories the next time named from hmm0 to hmm240. I want to always only take the last directory (and ignore previous ones). Is this possible, and if so how? If not, is there a better solution than just having to change the .gitignore file each time the number of directories change?

Answer 1

I would readjust the models directory, so to keep the important one in current and don't sync the archives.

In your code you would then implement something like(not working BASH ;) ):

archive_count=`ls -l | grep "^d" | wc -l`
mkdir /models/archive/hm$archive_count
mv  /models/current/* /models/archive/hm$archive_count/

models
    |-archive
        |-hm0
        |-hm1
    |-current
        |-current files

.gitignore
!/models/archive
/models/archive/*```