Guriddo Jqgrid - Multi-select filter issue

Question

I want to use multi-select filter in Guriddo jqgrid. But one of my record contains comma in the data. I want to filter those records using multi-select filter having comma in the data using delimiter as ';' and key value separator as ':'. My requirement is same as the link given in free version of jqgrid.

--Free jqgrid
https://jsfiddle.net/OlegKi/ty4e68pm/2/

--Guriddo jqgrid
https://jsfiddle.net/DhirendraM/1ebymu72/37/`

It is working in free jqgrid properly: jqGrid 4.15.5-pre - free jqGrid using the property: inFilterSeparator: ";" but not working in my sample with version @license Guriddo jqGrid JS - v5.8.5 - 2023.07-19.

Answer 1

free-jqGrid and Guriddo jqGrid are not 100% compatible. In all cases you will need to check the docs if you plan to do such conversion.

Here is the example with multiselect plugin:

Here is the doc for search type select options. Actually in your case you will need to use in searchoptions the multiseparator option (not documented here) which by default is ","