How can I print long long integer in xv6?

Question

I found out that I can not use "%llu" or "%lld" in xv6. All I could use is "%d" for printing integer. Is there any way I can print long long integer in xv6?

I tried converting long long to string, but things didn't go well.

Answer 1

You can split up the number. With a 32-bit int this should work for values up to 4294967295999999999.

#include <stdio.h>

int main(void) {

    unsigned long long n = 1234500000006789;
    //unsigned long long n = 4294967295999999999;
    unsigned int top = (unsigned int)(n / 1000000000);
    unsigned int bot = (unsigned int)(n % 1000000000);
    if(top)
        printf("%u%09u\n", top, bot);
    else
        printf("%u\n", bot);
}

Output

1234500000006789

For signed values, detect the sign first, output - and negate.