I am working on some c++ problem which should output 22258199.5000000 this number, I have stored the result in double datatype and when I tried to print that variable using std::cout it rounds off to 22258200.0000000, I don't know why is this happening? can anybody explain? what can I do to avoid this problem?
How to avoid rounding off of large float or double values?
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A 32-bit
floattype holds approximately 7 decimal digits, and anything beyond that will be rounded to the nearest representable value.A 64-bit
doubletype holds approximately 15 decimal digits and also rounds values beyond that.Since your value is rounding to the nearest 7-digit number, it appears you're using a
floatvariable somewhere. Copying afloatvalue todoubledoesn't restore the lost digits.This doesn't apply to your example, but it might in others - the rounding occurs in binary, not decimal, so you might end up with a value that appears to contain many more digits than I indicated above. Just know that only the first 7 or 15 are going to be accurate in decimal.