some code is as follow:
const ESTIMATEDSIZE = 10000
var init_arr = [...]int{1,1,2,3,5,8,13}
var fibbo []int = make([]int, len(init_arr), ESTIMATEDSIZE)
}
There is no reserved function like vector in c++ for slice fibbo to reserve ESTIMATEDSIZE for a slice to reduce the copy time on extending capacity. So I can only assign ESTIMATEDSIZE to capacity at initialization. But neither of below is legal.
var fibbo []int = init_arr[::ESTIMATEDSIZE]
var fibbo []int = make([]int{1,1,2,3,5,8,13}, len(init_arr), ESTIMATEDSIZE)
Are there any method to this question? Or may be the clumsy code as follow is the only way?
var fibbo []int = make([]int, len(init_arr), ESTIMATEDSIZE)
for i:= range init_arr {
fibbo[i] = init_arr[i]
}
No, this cannot be done. And it's part of the Go design philosophy that informs this design decision: "Don't hide complexity."
Your "clumsy" code is actually the preferred and idiomatic way to do this in Go, with one minor change:
(Other than formatting), the only change I made was to remove the type from the
vardeclaration, since that's entirely superflous. In other words:As pointed out in comments, you can also use the
copybuilt-in to eliminate the for loop, if you're not doing any other alterations on the inputs: