How to obtain the number of elements with classname "xyz" through Selenium

Question

Is it possible to do something like this? I want to know the number of elements with the class property set to 'gsc-cursor-page'.

pages_nav = driver.find_element_by_css_selector('.gsc-cursor')
pages = driver.find_element_by_css_selector('.gsc-cursor-page')
for pages in pages_nav:
    print("len(pages)")

As shown below are (.gsc-cursor-page) inside (.gsc-cursor) So how can I obtain the number of elements with classname 'gsc-cursor-page'.

Answer 1

To print the number of elements with classname property set to gsc-cursor-page you can use either of the following locator strategies:

• Using CLASS_NAME:

  print(len(driver.find_elements(By.CLASS_NAME, "gsc-cursor-page")))
  

• Using CSS_SELECTOR:

  print(len(driver.find_elements(By.CSS_SELECTOR, "[class='gsc-cursor-page']")))
  

• Using XPATH:

  print(len(driver.find_elements(By.XPATH, "//*[@class='gsc-cursor-page']")))
  

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Update

The output of 15, 13 and 13 is perfect as the xpath and the css_selector looks for the elements only with classname gsc-cursor-page i.e. perfect match and there can be some more elements outside the scope of the snapshot you provided and some more elements which also contains the classname gsc-cursor-page.

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Solution

Your effective line of code will be:

• Using CSS_SELECTOR:

  print(len(driver.find_elements(By.CSS_SELECTOR, "div.gsc-cursor div.gsc-cursor-page")))
  

• Using XPATH:

  print(len(driver.find_elements(By.XPATH, "//div[@class='gsc-cursor']//div[@class='gsc-cursor-page']")))
  

Answer 2

I think you can simply do

pages = driver.find_elements_by_css_selector('.gsc-cursor-page')

find_elements instead of find_element, which returns a list. And then you can count the number of elements in the list with

len(pages)