I was looking at the man page for brk(2), and it said that it increases the program break therefore allocating more memory to the heap. However, the way that I understand it, heap memory isn't always completely virtually contiguous in the PROG_TEXT -> PROG_HEAP (prog break) -> PROG_STACK manner that it seems to describe. Is the program heap actually virtually contiguous? If not, how does brk(2) work in a way that's consistent with what's described on the man page?
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Heap memory may or may not be contiguous.
malloc()is not restricted tosbrk()(sbrk()is what callsbrk()...) The standard mode is the small heap comes frombrk()and the big heap comes frommmap(); you are not expected to care about this as a user ofmalloc().sbrk()thus fragmenting the heap.On 64 bit processors there's a pretty good chance of running out of RAM before
brk()has to give up andmalloc()resorts tommap(); however this scenario can happen.Your code really shouldn't care. If you're in a situation that's so degenerate that you care (I was once on 32 bit where I needed almost all my address space for a single workspace) you are whole program constrained and need to turn off ASLR for your process. If that's your question, answer here: https://askubuntu.com/a/1355819/287855