Unity. Get the current IMGUI drawing target. Screen or EditorWindow/Popup

Question

I'm developing a class that can draw the interface both in the game and in the editor. Now I manually specify which mode to work. Because some functions are not available in different modes

class MyWindow : MonoBehaviour {
  void OnGUI() {
    myClass.OnGUI(GUIMode.Screen);
  }
}
 
class MyEditorWindow : EditorWindow {
  void OnGUI() {
    myClass.OnGUI(GUIMode.Inspector);
  }
}

I would like to learn how to detect this automatically. Is it possible?

What have already I tried: Google. Read documentation. Read Unity GUI-classes source code

Answer 1

There are scripting symbols you can use to conditionally compile things.
They can also be used to determine specific configurations of the environment, and set variables.
eg.

private bool isEditor;
...
#if UNITY_EDITOR

isEditor = true;

#endif

For specifically checking if you are in the editor, you can use the flag isEditor from the Application class.

if (Application.isEditor)
{
    Debug.Log("In Editor");
}
else
{
    Debug.Log("In Build");
}

There are more flags in the Application class to determine common environment context, such as isMobilePlatform, isConsolePlatform, platform, etc.