My question is: Why the compiler doesn't run my code if the symbol is declared?
I'm trying to run this code on Ubuntu Linux with gcc. But when I try to run it, it says "'i' not declared (first use in this function) return i - 1;". I googled several questions about it.
I'm starting with programming and C language and this code is not mine, it serves to calculate the greatest power of 2 that does not exceed N.
int power (int i) {
int p = 1;
for (int j = 1; j <= i; ++j) p = 2 * p;
return p;
}
int lg (int N) {
for (int i = 0; power (i) <= N; ++i) {}
return i - 1;
}
int main () {
power(2);
printf("%d", lg(2));
}
Variables declared in a the first expression of a
forloop are scoped to the statement. They only exist for the span of the statement (including the body of the loop).Fixed:
As an aside, we can greatly reduce the number of multiplications:
Instead of multiplying, we could divide.